2021-12-07 10:16:41 +01:00
|
|
|
import Data.List.Split
|
|
|
|
|
|
|
|
main :: IO ()
|
|
|
|
main = do
|
|
|
|
input <- readFile "7/input.txt"
|
|
|
|
let x = parse input
|
|
|
|
-- Problem 1
|
|
|
|
print $ f x
|
|
|
|
-- Problem 2
|
|
|
|
print $ g x
|
|
|
|
where
|
2021-12-07 13:29:48 +01:00
|
|
|
f x = solve distance [ minimum x .. maximum x ] x
|
|
|
|
g x | length x >= 100 = solve triangle [ sum x `div` length x ] x
|
|
|
|
| otherwise = solve triangle [ minimum x .. maximum x ] x
|
2021-12-07 10:16:41 +01:00
|
|
|
|
2021-12-07 13:29:48 +01:00
|
|
|
-- NOTE for part 2 (`g`):
|
|
|
|
-- Just testing against the mean value of `x` only gives accurate results if the
|
|
|
|
-- sample is large enough. Here, lists of size 100 or larger are deemed "large enough",
|
|
|
|
-- but that's pretty arbitrary.
|
|
|
|
|
|
|
|
-- | Split on comma and interpret each element as an integer
|
2021-12-07 10:16:41 +01:00
|
|
|
parse :: String -> [Int]
|
|
|
|
parse = map read . wordsBy (== ',')
|
|
|
|
|
2021-12-07 13:29:48 +01:00
|
|
|
-- | Solve the problem by finding the minimum of a list of integers, where
|
|
|
|
-- | each element is the total amount of fuel needed for each crab to reach
|
|
|
|
-- | that position.
|
|
|
|
solve :: (Int -> Int -> Int) -- ^ Fuel calculation to get between two points
|
|
|
|
-> [Int] -- ^ List of possible target positions
|
|
|
|
-> [Int] -- ^ List of initial positions
|
|
|
|
-> Int
|
|
|
|
solve f a x = minimum $ map g a
|
|
|
|
where
|
|
|
|
g t = sum $ map (f t) x
|
2021-12-07 10:16:41 +01:00
|
|
|
|
2021-12-07 13:29:48 +01:00
|
|
|
-- | Calculate the fuel usage based on the triangle number of the distance
|
|
|
|
-- | between the two numbers.
|
|
|
|
triangle :: Int -> Int -> Int
|
|
|
|
triangle a b = tri $ distance a b
|
|
|
|
where
|
|
|
|
tri n = n * (n + 1) `div` 2 -- Calculate nth triangle number
|
2021-12-07 10:16:41 +01:00
|
|
|
|
2021-12-07 13:29:48 +01:00
|
|
|
-- | Calculate the absolute distance between two numbers
|
2021-12-07 10:16:41 +01:00
|
|
|
distance :: Int -> Int -> Int
|
2021-12-07 13:29:48 +01:00
|
|
|
distance a b = abs (a - b)
|